求助这道题怎么解？谢谢！

[1/（1-x)-1/(1+x)]÷(x/(x²-1)+x]=[(1+x)/(1-x²)-(1-x)/(1-x²)]÷[x(x²-1+1)/(x²-1)]=2x/(1-x²)÷[x*x²/(x²-1)]=-2/x²∵x²/(x²-2)=1/(1-√3-√2)∴(x²-2)/x²=1-√3-√2则：1-2/x²=1-√3-√2计：-2/x²=-√3-√2所以：原式=-√3-√2