求导数f(x,y)

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收藏|2019/12/31 03:03

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2019/12/31 03:10

∂f/∂x=[kcosxcosysin(x-y)-ksinxcosycos(x-y)]/sin²(x-y)=-½ksin2y/sin²(x-y)∂f/∂y=[-ksinxsinysin(x-y)+ksinxcosycos(x-y)]/sin²(x-y)=½ksin2x/sin²(x-y)全微分:df=[½k/sin²(x-y)](-sin2ydx+sin2xdy)

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