19.某校六年级原有两个班，现在要重新编为

设：原一班有x人，原二班有y人。依题意：新一班人数=1/3x+1/4y；新二班=1/4x+1/3y由新一班的人数比新二班的人数多10%（即1/10)可得：[(1/3x+1/4y)-(1/4x+1/3y)]/(1/4x+1/3y)=1/101/12(x-y)/[1/12(3x+4y)]=1/10(x-y)/(3x+4y)=1/1010(x-y)=3x+4y 10x-10y=3x+4y 7x-14y=0 x-2y=0 (1)(x+y)-(1/3x+1/4y+1/4x+1/3y)=60(x+y)-7/12(x+y)=60 5/12(x+y)=60 x+y=144 (2)(2)*2+(1)得：3x=288 x=96答：原一班有96人。