题目如下,求因式分解。

zhong_530 |浏览527次
收藏|2020/03/26 13:12

满意回答

2020/03/26 13:20

1.x²+10x+21=(x+7)(x+3)2.x²+6x+5=(x+1)(x+5)3.x²+6x-16=(x+8)(x-2)4.x²-17x+16=(x-1)(x-16)5.x²-x-12=(x-4)(x+3)6.x²+2x-15=(x+5)(x-3)7.x²-5x-6=(x-6)(x+1)8.x²+11x+24=(x+3)(x+8)9.x²+10x+21=(x+7)(x+3)10.x²+4x-12=(x+6)(x-2)11.x²+4x+4=(x+2)(x+2)12.x²+10x+25=(x+5)(x+5)13.x²-8x+16=(x-4)(x-4)

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其他回答(2)
  • 1.x²+10x+21=(x+3)(x+7)2.x²+6x+5=(x+1)(x+5)3.x²+6x-16=(x+8)(x-2)4.x²-17x+16=(x-1)(x-16)5.x²-x-12=(x-4)(x+3)6.x²+2x-15=(x+5)(x-3)7.x²-5x-6=(x-6)(x+1)8.x²+11x+24(x+3)(x+8)9.x²+10x+21=(x+3)(x+7)10.x²+4x-12=(x+6)(x-2)11.x²+4x+4=(x+2)²12.x²+10x+25=(x+5)²13.x²-8x+16=(x-4)²14.二次三项式x²+mx-15可因式分解为(x-5)(x+n),则m=-2 n=3.
    回答于 2020/03/26 13:48
  • 1. x²+10x+21=(x+7)(x+3) 2. x²+6x+5=(x+5)(x+1)3. x²+6x-16=(x+8)(x-2)4.x²-17x+16=(x-16)(x-1)5.x²-x-12=(x-4)(x+3)6. x²+2x-15=(x+5)(x-3)7.x²-5x-6=(x-6)(x+1)8.x²+11x+24=(x+8)(x+3)9.x²+10x+21=(x+7)(x+3)10.x²+4x-12=(x+6)(x-2)11.x²+4x+4=(x+2)²12.x²+10x+25=(x+5)²13.x²-8x+16=(x-4)²14.x²+mx-15=(x-5)(x+n)x²+mx-15=x²+nx-5x-5nx²+mx-15=x²+(n-5)x-5n5n=15 n=3;m=n-5 m=3-5 m=-2结果:m=-2 n=3。
    回答于 2020/03/26 13:28
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