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收藏|2020/04/16 11:10

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检举 |2020/04/16 11:29

12x^5-6x^4-7x^3+2x^2+x+1=4x^2(3x^3-x+1)-2x(3x^3-x+1)-(3x^3-x+1)-4x^2+2x+2(3x^3-x+1)(4x^2-2x-1)-(4x^2-2x-1)+1=12x^3-x+1=(1/2)(4x^3-2x+2)=(1/2)[x(4x^2-2x-1)+2x^2-x+2]=(1/2)[x(4x^2-2x-1)+(1/2)(4x^2-2x-1)+5/2]=(1/2)[(4x^2-2x-1)(x+1/2)+5/2]=5/4(12x^5-6x^4-7x^3+2x^2+x+1)/(2x^3-x+1)=4/5希望对你有帮助，回答不易，望采纳！

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秀才 | 采纳率100% | 回答于 2020/04/16 11:29

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欧雷克

12x^5-6x^4-7x^3+2x^2+x+1=4x^2(3x^3-x+1)-2x(3x^3-x+1)-(3x^3-x+1)-4x^2+2x+2=(3x^3-x+1)(4x^2-2x-1)-(4x^2-2x-1)+1=12x^3-x+1=(1/2)(4x^3-2x+2)=(1/2)[x(4x^2-2x-1)+2x^2-x+2]=(1/2)[x(4x^2-2x-1)+(1/2)(4x^2-2x-1)+5/2]=(1/2)[(4x^2-2x-1)(x+1/2)+5/2]=5/4(12x^5-6x^4-7x^3+2x^2+x+1)/(2x^3-x+1)=4/5
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回答于 2020/04/16 11:50
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CH58JR

(2x+y)^2-8xy=4x^2+4xy+y^2-8xy=4x^2-4xy+y^2=(2x-y)^2
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回答于 2020/04/16 11:42
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