电感电流i = 200∠30°/( 100 + j100 ) =200∠30°/( 100√2∠45°) =√2∠-15°;等效电压uab = uL = i *xL =√2∠-15° * 100∠90° = 100√2∠75° v;等效阻抗zab = R//xL + xC= 100 * j100/( 100 + j100 ) - j200= 10000∠90°/( 100√2∠45°) - j200= 50√2∠45° - j200= 50 + j50 - j200= 50 - j150 Ω 。