请问这道题一元一次方程怎么解

匿名网友 |浏览708次
收藏|2020/06/12 09:06

满意回答

2020/06/12 09:15

75%(x-600)/8000=75%(x-1200)/6000(x-600)/8=(x-1200)/66(x-600)=8(x-12006x-3600=8x-96008x-6x=9600-36002x=6000x=3000

匿名网友

其他回答(3)
  • (x-400-200)*(1-25%)/(6000+2000)=(x-400-800)*(1-25%)/6000解:(x-600)*0.75/8000=(x-1200)*0.75/6000(x-600)*0.75*3=(x-1200)*0.75*4(x-600)*3=(x-1200)*43x-1800=4x-4800x=3000
    回答于 2020/06/12 10:32
  • (x-400-200)*(1-25%)/(6000+2000)=(x-400-800)*(1-25%)/6000(x-600)/8000=(x-1200)/6000(x-600)/4=(x-1200)/34(x-1200)=3(x-600)4x-4800=3x-1800x=3000
    回答于 2020/06/12 10:01
  • (x-400-200)(1-25%)/(6000+2000)=(x-400-800)(1-25%)/6000(x-600)/8000=(x-1200)/60003(x-600)=4(x-1200)3x-1800=4x-48003x-4x=1800-4800-x=-3000x=3000
    回答于 2020/06/12 09:32
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