计算：求下列式子的整数部分是多少

A=1+1/2+1/3+1/4+……+1/16A=1+1/2+(1/3+1/4)+(1/5+1/6+1/7+1/8) =(1/9+1/10+1/11+1/12+1/13+1/14+1/15+1/16)A>1+1/2+2*1/4+4*1/8+8*1/16 =1+1/2+1/2+1/2+1/2 =3A<1+1/2+2*1/4+(1/3-1/4)+4*1/8+(1/5-1/8)*3+8*1/16+(1*9-1/16)*7 =3+(1/12+9/40+49/144) <4∵ 3<A<4，∴ [A]=3