一次提问太多,下次请分开提问。9、选A 。z = u/i =√2∠-45° =√2[ cos(-45°) + jsin(-45°) ] = 1 - j,即电阻、电容串联;ω = 1,1/(ωc) = 1,C = 1F;R = 1Ω 。16、选B 。I不变,只能是Ic - IL = IL,ωL = 2(1/ωC) = 2 * 100 = 200Ω;L = 200/ω = 200/10 = 20H;17、选A.电桥四臂阻抗相等,uR = uc,电位差为 0v 。20、选C .道理同上。z电流为零,说明电桥平衡,R *R =ωL * 1/ωC;1/ωC = 10 * 10/4 = 25Ω;21、选C 。这个电路称文氏电桥。u1与 u2同相,则RC串联电路两端电压u3也与 u2同相;因为串联部分与并联部分流过同一个电流,所以两部分阻抗也同相;z1 = R - j(1/ωC) = 20000 - j( 10^6/ω ),阻抗角 tanφ = -10^6/( 20000ω ) = -50/ω;并联部分导纳 Y2 = 1/R + 1/(-j/ωC) = 1/R + jωC = 50/10^6 + j25ω/10^10;z2 导纳角tanφ =25ω/10^10/(50/10^6 ) =ω/20000;z2阻抗角tanφ = -ω/20000;故ω/20000 = 50/ω,ω^2 = 10^6,ω = 10^3;22、选C 。150 - 50 = 100 v,说明并电感后,z2电压相位与z1相反;所以z1是容性阻抗 -jx;z2并电感后,由容性阻抗变为感性阻抗;Y2 = 1/(j50) + 1/(-jx) = -j0.02 + j(1/x) = -j( 0.02 - 1/x );z2 = 1/Y2 = j [ 1/( 0.02 - 1/x ) ]x/[ 1/( 0.02 - 1/x ) ] = 150/50 = 3,0.02x - 1 = 3,x = 200;23、选C。短路端口;6A电流一半流向左边1Ω,一半经右边1Ω流向端口;4A电流源被端口短路,所以全部流向端口。等效电源电流为 (6/2)sinωt + 4cosωt = 5cos(ωt - 36.8° ) A。27、选D( v3 - v2 )^2 = v^2 - v1^2 = 100 - 36 = 64v3 = v2± 8 = 3 ± 8,取正号,v3 = 11v 。28、选B 。A =√( A1^2 + A2^2 ) =√( 5^2 + 12^2 ) = 13 A