(2x-y)(y+2x)-(2y+x)(2y-x),其中x=1化简求值

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收藏|2022/06/23 07:02

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2022/06/23 07:30

(2x-y)(y+2x)-(2y+x)(2y-x)=[(2x²-y²]-[(2y)²-x²]=4x²-y²-4y²+x²=5x²-5y²//(2x-y+3z)(-2x-y-3z)-(x+2y-3z)²=[-y+(2x+3z)][-y-(2x+3z)]-[2y+(x-3z)]²=(-y)²-(2x+3z)²-(2y)²-2(2y)(x-3z)-(x-3z)²=y²-4y²-(4xy-12yz)-(4x²+12xz+9z²)-(x²-6xz+9z²)=-3y²-5x²-18z²-4xy+12yz-6xz=-3*1-5*1-18*1-4(-1)+12(-1)-6*1=-3-5-18+4-12-6=-40直接代入原式=(2+1+3)(-2+1-3)-(1-2-3)²=6*(-4)-(-4)²=-24-16=-40多简单

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其他回答(1)
  • (2x-y)(y+2x)-(2y+x)(2y-x)=(4x²-y²)+(x²-4y²)=4x²-y²+x²-4y²=5(x²-y²)=5×(1-y²)=5-5y²(2x-y+3z)(-2x-y-3z)-(x+2y-3z)²=-(2x-y+3z)(2x+y+3z)-(x+2y-3z)²=-(2x+3z)²+y²-(x+2y-3z)²=-(2×1+3×1)²+(-1)²-(1-2×1+3×1)²=-25+1-4=-28
    回答于 2022/06/23 07:50
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