化简根号1-sin200°

√( 1 -sin200° )=√[ (sin100°)^2 + (cos100°)^2 - 2sin100°cos100°]= √[ ( sin100° + cos100°)^2 ] 【 ∵ sin100° + cos100° > 0 】=sin100° + cos100°=√2sin(100° + 45° )=√2sin(180° - 35° )=√2sin35° 。