设A=1100,0011,-2022,0-303,求矩阵的秩

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收藏|2022/11/27 11:04

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2022/11/27 11:19

1 1 0 0 1 1 0 0 0 1 0 0 0 1 0 0 0 1 0 00 0 1 1 = 0 0 1 1 = 0 0 1 1 = 0 0 1 1 = 0 0 1 0-2 0 2 2 -2 0 0 0 -2 0 0 0 -360问答2 0 0 0 -2 0 0 00 -3 0 3 0 -3 0 3 0 -3 0 3 0 0 0 3 0 0 0 3A的秩=4

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