如何求导y=³√(√(x³+6)+√(x³+x²+4x+30))?要详细过程,谢谢。

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收藏|2022/11/29 17:05

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2022/11/29 17:26

y=³√[√(x³+6)+√(x³+x²+4x+30)]①建父怀仅赶厚击期概y³=√(x³+6)+√(x³+x²+4x+30)设z₁=√(x³+6)②,z₂=√(x来自³+x+4x+30)③z₁²=x³+62z₁z₁'=3x²,z₁'=(3x²)/(2z₁)=(3x²/2)/z₁④z₂²=x³+x²+4x+302z₂z₂'=3x²+2x+4z₂'=(3x²+2360问答x+4)/(2z₂)=(3x²/2+x+2)/z₂⑤y³=z₁+z₂3y²y'=z₁'+z₂'y'=(z₁'+z₂')/(3y²)把②③④⑤代入,整理。

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  • 幂函数 y = x^n的求导般房质公式:y' =nx^(n-1)复合函数求定著细黑玉乱孔副导:y = u(v(x)),y' = u'(v) * v'(x)y = [ ( x^3 + 6 )掌水否营免课^(1/2) + ( x^3 + 低节十剧重定八业x^2 + 4x + 30 )^要一比席上大(1/2) ]^(1/3)y' = (1/3武)[ ( x^3 + 6 )^(1/2) + ( x^3 + x^2 + 4x + 30 )^(1/2) ]^( 1/3 - 1 ) *[ ( x^3 + 6 )^(1/2) + ( x^3 + 调款器流x^2 + 4x + 30 )^(1/2) ]'=(1/3)[ ( x^旧责良甲3 + 6 )^(1/2) 赵沉主学+ ( x^3 + x^2 + 4x + 30 )^(1/2) ]^( -2/3 ) *{[ ( x^3 + 6 )^(1/2) ]' + [ ( x^3 采交失牛协+ x^2 + 4x + 30 )^各哪信总排本顶放看脱田(1/2) ]' }=(1/3)[ ( x^3 灯极独技可速张+ 6 )^(1/2) + ( x^3 + x^2 + 4x + 30 )^(1/2) ]^( -2/3 ) *{ (1/2)( x^3 + 6 )^( 1/2 - 1) * ( x^3 + 6 )'+ (1/2)( x^烟3 + x^2 + 4x + 30 )^( 1/2 - 1 ) *( x^3 + x^研哥形取有对板载2 + 4x + 30 )' }= (1/3)[ ( x^3 + 6 )^(1/2) + ( x^3 + x^2 + 4x + 30 )^(1/2) ]^( -2/3 ) *(1/2)[ ( x^3 + 6 )^( -1/2 ) * 3x^2 + ( x^3 + x^2 + 4x + 30 )^击吸省映虽(-1/2) * ( 3x^2 + 2x + 4 ) ]
    回答于 2022/11/29 17:35
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